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Consider the following cache A and B .let the average access times in cache A and B is $t_A$ and $t_B$ respectively.the value of $t_A+t_B$ _(in ns)

Answer is given as 30.18 ns

I am getting 31.2 ns .Please verify it .

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By default memory access in cache is hierarchical.

For A

EMAT = $5 + 0.2 * 80 = 21 ns$

For B

EMAT = $3 + 0.4( 6 + 0.15*80) = 10.2 ns$

So sum = $31.2ns$

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