Testbook Test Series: Computer Networks - Tcp

Question

TCP opens a connection using an initial sequence number of 3500 and sends data at 5 MBps. The other party opens the connection with a sequence number of 1200. Wrap around time for both the sequence numbers differ by 12562.77 sec. Calculate the data rate(in KB) for the second party.

Comments

we are using sequence number for each byte 5MB in 1 sec so why not 5 * 2^20 Sequence numbers in 1 sec?

---

@Utkarsh Joshi It has nothing to do with the initial sequence numbers right?

---

@Utkarsh Joshi

Here intital sequence number doesn't matters ..for any TCP connection Wrap around time depends on BW and Sequence number bits ..right ??