# made easy test series (network security)

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$3599=59*61$

$\phi(n)=(59-1)*(61-1)=3480$

$d*e\equiv (1)mod(3480)$

After solving a lot

$d = 3031$
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i got d=449. after that how did we get 3031 i need to understand that?
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(449*31)3480 is not 1
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its d= -449 so it will be 3480-449= 3031
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multiplicative inverse

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DH key exchange algorithm is used to establish a session between sender and receiver with n=23 and g=5. The sender's secret key is 6 and the receiver's secret key is 15. What is the secret key between the receiver and sender? Please explain with solution P.S: Answer is given as 2