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in CO and Architecture by Boss (48.6k points) | 53 views
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64 registers => 6 bits => option 3.

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$1$ indirect bit

$log_2 64 = 6$ bits for registers

$18$ bits for address ($2^{18} = 256K$)

Bits for operation code = $32-1-6-18 = 7$

$3. \ \ \  7, 6 , 18 $ is the answer
by Boss (35.4k points)

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