Question: TCP opens a connection using an initial sequence number of 3500 and sends data at a rate of 5MBps. The other party opens a connection with a sequence number of 1200. Wrap around time for both sequence number differs by 12562.77 sec. Calculate the data rate (in KBps) for the second party.
The answer given is 320-321 but I calculated the answer to be 366.9.
In the solution, they calculated WAT as $\frac{2^{_{32}}-Initial Sequence}{Bandwidth}$
Whereas I calculated WAT as $\frac{2^{_{32}}}{Bandwidth}$
Which one is correct?