0 votes 0 votes If the time taken by a task to get completed is same in the pipeline and non pipeline circuits, then how the time taken to complete the task in non pipeline = k* time taken to complete the task in pipeline where k is no. of segments in the pipeline? CO and Architecture co-and-architecture pipelining + – Nivedita Singh asked Dec 27, 2018 • edited Dec 27, 2018 by Nivedita Singh Nivedita Singh 376 views answer comment Share Follow See 1 comment See all 1 1 comment reply MiNiPanda commented Dec 27, 2018 reply Follow Share If you take one task and execute in non-pipeline and it's corresponding pipelined architecture having k stages each of equal length then the time taken by both will be same. If the stage delays are different, then for a single task, pipeline will take more time than non Pipelined one. But if you consider for a *large number of tasks* then you will understand the difference that time taken by pipelined one is much less. 2 votes 2 votes Please log in or register to add a comment.
0 votes 0 votes It is applicable only for the first instruction Psy Duck answered Sep 6, 2022 Psy Duck comment Share Follow See all 0 reply Please log in or register to add a comment.