A. $\frac{a}{b}$ = $\frac{c}{d}$ $\Rightarrow$ $\frac{a}{b}$ + 1 = $\frac{c}{d}$ + 1 $\Rightarrow$ $\frac{a+b}{b}$ = $\frac{c+d}{d}$ ✔
B. $\frac{a}{b}$ = $\frac{c}{d}$ $\Rightarrow$ $\frac{a}{c}$ = $\frac{b}{d}$
Using Componendo, $\frac{a+c}{c}$ = $\frac{b+d}{d}$
Using Dividendo, $\frac{a-c}{c}$ = $\frac{b-d}{d}$
By dividing both, we get $\frac{a+c}{a-c}$ = $\frac{b+d}{b-d}$ $\Rightarrow$ $\frac{a+c}{b+d}$ = $\frac{a-c}{b-d}$ ✔
C. $\frac{a}{b}$ = $\frac{c}{d}$
Using Componendo, $\frac{a+b}{b}$ = $\frac{c+d}{d}$
Using Dividendo, $\frac{a-b}{b}$ = $\frac{c-d}{d}$
By dividing both, we get $\frac{a+b}{a-b}$ = $\frac{c+d}{c-d}$ ✔
So D is the answer