where is the 4 Bytes ??? 1st Byte i just 6 bit.

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Shankar Kakde
asked
in Digital Logic
Dec 28, 2018

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Here 64 encoding is asked so make group of 6 bits because 2^6=64

First group 101000 it corresponds to 40 which is o

Second group 110011 it corresponds to 51 which is z

third group 011111 it corresponds to 31 which is f

fourth group 101001 it corresponds to 41 which is p

fifth group 101010 it corresponds to 42 which is q Hence ozfpq D is the answer

First group 101000 it corresponds to 40 which is o

Second group 110011 it corresponds to 51 which is z

third group 011111 it corresponds to 31 which is f

fourth group 101001 it corresponds to 41 which is p

fifth group 101010 it corresponds to 42 which is q Hence ozfpq D is the answer