in Digital Logic
162 views
0 votes
0 votes

in Digital Logic
162 views

1 comment

where is the 4 Bytes  ??? 1st Byte i just 6 bit.
0
0

1 Answer

0 votes
0 votes
Here 64 encoding is asked so make group of 6 bits because 2^6=64

First group 101000 it corresponds to 40 which is o

Second group 110011 it corresponds to 51  which is z

third  group 011111 it corresponds to 31 which is f

fourth group 101001 it corresponds to 41 which is p

fifth group 101010 it corresponds to 42 which is q Hence ozfpq D is the answer