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asked in Set Theory & Algebra by (147 points) | 39 views
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D?
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Yes both are false

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S1 : LHS : $X\vee (Y\wedge Z) = X\vee$ O = X  ($\wedge$ = GLB, $\vee$ = LUB)

        RHS: ($X\vee Y)\wedge $Z = I $\wedge$ Z = Z

        so LHS $\neq$ RHS similarly S2 also

 

Ans: D
answered by Active (3.4k points)

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