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Suppose A and B are on same 10Mbps ethernet segment and the propogation delay between nodes is 225 bit times.
Suppose A and B send frames at t=0 , the frames collide then at what time they finish travelling a 48 bit jam signal ?

In this question how come propogation delay is in bit times , it should be transmission time which is equal to length of frame / bandwidth .

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what u can do find time for transmit 255 + 48 bits then multiply by b.w. 

simple when propagation time is present then if multiply by b.andwidth. with round trip time  come in bits.

Suppose A and B send frames at t=0 , the frames collide then at what time they finish travelling a 48 bit jam signal then at frame frame size 512 jamming signal is sent.

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Sir propogation time =distance/velocity ,it is transmission time =size of frame / bandwidth
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