0 votes 0 votes closed with the note: Got the answer Solve this. Digital Logic made-easy-booklet self-doubt digital-logic decoder + – Jyoti Kumari97 asked Dec 30, 2018 closed Dec 30, 2018 by Jyoti Kumari97 Jyoti Kumari97 820 views comment Share Follow See all 2 Comments See all 2 2 Comments reply register_user_19 commented Dec 30, 2018 reply Follow Share f = D0 + D1 = (~A1 . ~A0) + (~A1 . A0) = (~A1) = ~(D2 . D3) = ~( (A1 . ~A0) . (A1 . A0) ) = ~( (x . ~y) . (x . y) ) = (~(x . ~y) + ~(x.y) ) = ( (~x + y) + ~x + ~y ) = (~x + ~x + y + ~y) = 1 option d) 0 votes 0 votes Shamim Ahmed commented Dec 30, 2018 reply Follow Share 1 is the answer 0 votes 0 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes Input to the 2nd Decoder is x'y.xy = 0 f = A0'A1' + A0A1' = z' + z = 1 Thus the Answer must be 1 . Correct me if I went wrong somewhere. prashant jha 1 answered Dec 30, 2018 selected Dec 30, 2018 by Jyoti Kumari97 prashant jha 1 comment Share Follow See 1 comment See all 1 1 comment reply Jyoti Kumari97 commented Dec 30, 2018 reply Follow Share Thanks @prashant jha 1 1 votes 1 votes Please log in or register to add a comment.