If probability of frame reaching safely is 0.1 then mean number of transmissions of a frame to make it success is _____.
what is wrong with the approach given below
‘random variable x is the number of transmission’
X |
1 |
2 |
3 |
4… so on |
P(X) |
0.1 |
0.9*0.1 |
0.9*0.9*0.1 |
0.9*0.9*0.9*0.1 |
mean or expectation value of random variable E[X]= $\sum X*P(X)$
which comes out to be 100.
but given the answer is 10 using 1/p.
(what is wrong in above aproach?)