Here the answer is B)8.4
Suppose when there is cache “Miss” then memory Access is 30nsa and when cache “Hit” then memory access time is 3ns if 80% is cache hit then effective memory access
Ans: 8.4ns
0.8*3+0.2*30
A cache memory needs an access time of 3 ns and main memory 30 ns, what is average access time of CPU (assume hit ratio = 80%)?
Ans: 9ns
0.8*3+0.2*33