0 votes 0 votes Consider a vocabulary with only four propositions A, B, C and D. How many models are there for the following sentence? $\neg A \vee \neg B \vee \neg C \vee \neg D$ $7$ $8$ $15$ $16$ Unknown Category ugcnetcse-dec2018-paper2 + – Arjun asked Jan 2, 2019 edited Jun 22, 2020 by soujanyareddy13 Arjun 3.4k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes The answer should be option C 15. Tishya Manna answered May 31, 2019 Tishya Manna comment Share Follow See 1 comment See all 1 1 comment reply Prajna commented Jun 24, 2019 reply Follow Share please explain it. 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes $\sim A\vee \sim B\vee \sim C \vee \sim D$ is nothing but OR of $\sim A$, $\sim B$,$\sim C$ and $\sim D$ The truth table of the following model is shown below $\sim A$ $\sim B$ $\sim C$ $\sim D$ Output 0 0 0 0 0 0 0 0 1 1 0 0 1 0 1 0 0 1 1 1 0 1 0 0 1 0 1 0 1 1 0 1 1 0 1 0 1 1 1 1 1 0 0 0 1 1 0 0 1 1 1 0 1 0 1 1 0 1 1 1 1 1 0 0 1 1 1 0 1 1 1 1 1 0 1 1 1 1 1 1 Since there are 15 $1's$ in the truth table $\therefore$ option C. should be the correct answer Satbir answered Jun 24, 2019 Satbir comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes There are four variables A,B,C,D. Therefore 2^4= 16 total 16 element so 0 to 15 15 is the right answer Option c is the correct answer Nbhardwaj answered May 16, 2020 Nbhardwaj comment Share Follow See all 0 reply Please log in or register to add a comment.