0 votes 0 votes Match List-I with List-II and choose the correct answer from the code given below : $\begin{array}{|c|c|c|c|} \hline & \textbf{List I} & & \textbf{List II} \\ \hline (a) & Equivalence & (i) & p \Rightarrow q \\ \hline (b) & Contrapositive & (ii) & p \Rightarrow q; q \Rightarrow p \\ \hline (c ) & Converse & (iii) & p \Rightarrow q: \sim q \Rightarrow \sim p \\ \hline (d) & Implication & (iv) & p \Leftrightarrow q \\ \hline \end{array}$ (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv) (a)-(ii), (b)-(i), (c)-(iii), (d)-(iv) (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i) Mathematical Logic ugcnetcse-dec2018-paper2 mathematical-logic + – Arjun asked Jan 2, 2019 recategorized Jun 23, 2022 by Arjun Arjun 2.4k views answer comment Share Follow See 1 comment See all 1 1 comment reply Magma commented Jan 2, 2019 reply Follow Share D ) 0 votes 0 votes Please log in or register to add a comment.
Best answer 1 votes 1 votes (a) - (iv) (b) - (iii) (c) - (ii) (d) - (i) https://en.wikipedia.org/wiki/Converse_(logic) https://en.wikipedia.org/wiki/Contraposition https://en.wikipedia.org/wiki/Logical_equivalence https://en.wikipedia.org/wiki/Implication Option (d) Peeyush Pandey answered Jan 2, 2019 selected Jan 2, 2019 by Arjun Peeyush Pandey comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes $p\rightarrow q$ Equivalence : $p\rightarrow q\,\wedge\,q\rightarrow p $ Contrapositive : $\neg q\rightarrow \neg q$ Converse : $q\rightarrow p$ Implication : $p\rightarrow q$ $D\,)$ must be the answer Shobhit Joshi answered Jan 2, 2019 Shobhit Joshi comment Share Follow See all 0 reply Please log in or register to add a comment.