202.10.4.230/27
every octet made up of bits
8+8+8 = 24
BUT IN THE ABOVE QUESTION IT IS GIVEN 27 AND HENCE FROM THE LAST OCTET 3 BITS ARE GIVEN
230 IN BINARY 111(00110) MAKE EVRY BIT ONE IN THE BRACKET THAT WILL BE THE BROADCAST ADDRESS
1(111111) - 254 THIS IS LAST HOST
SO 202.104.253 IS LAST BUT ONE HOST