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Consider the following circuit:

  1. It outputs x+y
  2. It outputs y-x
  3. It outputs x+1
  4. It outputs y+1

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See, given is 4 bit adder,

And, X⊕1= ~X   //  1⊕1=0  or 0⊕1=1

So, X3X2X1X0 ⊕ operation with 1 will give 1's complement of it.

And as we know , 2's complement = 1's complement +1   // here, Gn =1

So, Here, Y-X= Y+(2's complement of X)

Option B

 

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