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closed as a duplicate of: madeeasy test series
#include<stdio.h>
int main()
{
    code(4);
    return 0;
}
int code(int m)
{
    if(m>0){
        int i=1;
        for(;i<3;i++){
            code(m-i);
            code(m-i-1);
            printf("MadeEasy");
        }
    }

return 0;
}

the number of times made easy will be printed? plz explain in detail
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Markzuck asked Jan 10, 2019
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Please explained detialed execution of this code, I am not getting how int stored in char, like we can interchange using ASCII but still cant store right?