0 votes 0 votes closed with the note: solved R is real no(does not contain -1) ,S is subset of R then (S,*) 1.not group but monoid 2.not abelian group but group 3.Abelian Group 4.not semigroup but groupid Abhisek Tiwari 4 asked Jan 5, 2019 • closed Jan 5, 2019 by Abhisek Tiwari 4 Abhisek Tiwari 4 232 views comment Share Follow See all 3 Comments See all 3 3 Comments reply Abhisek Tiwari 4 commented Jan 5, 2019 reply Follow Share @Magma @Gupta731 @Deepanshu 0 votes 0 votes Magma commented Jan 5, 2019 reply Follow Share S is a subset of R then there is a case when S = {1,2} when it violate the algebraic property right ?? I'm not sure but I think answer should be D ?? 0 votes 0 votes Abhisek Tiwari 4 commented Jan 5, 2019 reply Follow Share Ans is 3 0 votes 0 votes Please log in or register to add a comment.
