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QUESTION 2.16:

Solution:

Each word is of size: 32 bits = 32/8 Bytes = 4 Bytes.

Program has been loaded starting from memory location :1000.

Instruction Size                
2Words=8Bytes    1000    1001    1002    1003    1004    1005    1006    1007
1Word=4Bytes    1008    1009    1010    1011        
1Word=4Bytes    1012    1013    1014    1015        
2Words=8Bytes    1016    1017    1018    1019    1020    1021    1022    1023
1Word=4Bytes    1024    1025    1026    1027        
                 

After halt instruction memory location will be : 1027+1 = 1028.

Ans: 1028 Option D.

 

Hope it helps..!

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