0 votes 0 votes If $L = \{a^nb^n : n\geq 0\}$ then, $L^2=?$ Theory of Computation theory-of-computation + – aimhigh asked Jan 6, 2019 • edited Jan 6, 2019 by Arjun aimhigh 583 views answer comment Share Follow See all 9 Comments See all 9 9 Comments reply Show 6 previous comments aimhigh commented Jan 8, 2019 reply Follow Share How you all are tagging to other users I have also written correct names but it is just plain text 0 votes 0 votes Shaik Masthan commented Jan 8, 2019 reply Follow Share to tag someone, first type @, then type name 0 votes 0 votes aimhigh commented Jan 8, 2019 reply Follow Share @Shaik Masthan 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes $L^2 =L.L =a^nb^na^mb^m |n,m>=0$ abhishekmehta4u answered Mar 26, 2019 • edited Mar 27, 2019 by akash.dinkar12 abhishekmehta4u comment Share Follow See all 0 reply Please log in or register to add a comment.