parameter passing

Question

#include<stdio.h>
int fun(int arr[])
{
    arr=arr+1;
    printf("%d",arr[0]);
}
int main(void){
    int arr[2]={10,20};
    fun(arr);
    printf("%d",arr[0]);
    return 0;
}

A.COMPILE ERROR   B.20,10

C.10,20       D.20,20

Comments

B ?

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See this code to understand.


#include<stdio.h>
int fun(int a[])
{
    a=a+1;
    printf("%d ",a[0]);
    printf("%d ", a[1]);
}

int main(void){
    int arr[2]={10,20};
    fun(arr);
    printf("%d %d ",arr[0], arr[1]);
    return 0;
}

 

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i m thinking compiler error

array base address can not be changed

---

not compile error it gives output but i want know the procees of execution.

Answer 1

int fun(int arr[])   // arr will point to first element of the array
{
    arr=arr+1; // now arr will point to next element  
    printf("%d",arr[0]); // Second element is 20 & it will print
}
int main(void){
    int arr[2]={10,20};
    fun(arr);
    printf("%d",arr[0]); // first element is 10 ,So it will print that value.
    return 0;
}