Percentage CPU consumed in load

Question

𝗪𝗶𝗸𝗶𝗽𝗲𝗱𝗶𝗮 𝘀𝗮𝘆𝘀 𝘁𝗵𝗶𝘀 𝗮𝗯𝗼𝘂𝘁 𝗗𝗠𝗔 𝗯𝘂𝗿𝘀𝘁 𝗺𝗼𝗱𝗲 (https://en.wikipedia.org/wiki/Direct_memory_access#Burst_mode)

In burst mode, an entire block of data is transferred in one contiguous sequence. Once the DMA controller is granted access to the system bus by the CPU, it transfers all bytes of data in the data block before releasing control of the system buses back to the CPU, but renders the CPU inactive for relatively long periods of time. The mode is also called "Block Transfer Mode".

𝗔𝗯𝗼𝘂𝘁 % 𝗖𝗣𝗨 𝗰𝗼𝗻𝘀𝘂𝗺𝗲𝗱, 𝘁𝗵𝗶𝘀 𝗹𝗶𝗻𝗸 (https://gateoverflow.in/116524/coa-dma-doubt?show=116876#a116876) 𝘀𝗮𝘆𝘀:

% CPU consumed = [ (Initial time + termination time)/ total time ] * 100

where, total time = Initial time + termination time = transfer time

OR in other words,

total time = bus grant time + bus release time + transfer time

 

𝗧𝗵𝗶𝘀 (https://gateoverflow.in/37355/dma-operation?show=63806#a63806) 𝗽𝗿𝗼𝗯𝗹𝗲𝗺 𝘀𝗮𝘆𝘀

% of time cpu consumed is: 2/(2+64)

that is,

% CPU consumed = cycle-time / (cycle_time + transfer_time)

 

𝗗𝗼𝘂𝗯𝘁𝘀

1. Dont you think that two gateoverflow links give different formula?

2. CPU dont hold bus for full duration of (bus grant time + bus release time + transfer time). So should we consider this full duration as CPU consumed or just (bus grant time + bus release time)?