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asked in Digital Logic by Loyal (9.2k points)
edited by | 75 views
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$PI=5,EPI=2?$
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3????
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I am getting 3.Whats the answer?
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can you show ,how you got $3?$
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The 1 in the top left corner constitute 1EPI and the 1 in the bottom right corner constitute 1 EPI.Now the other 1's have to clubbed with the quad in order to get minimised expression.Hence getting 3.

Please correct me if I am wrong
+3

see this

please correct me if i'm wrong?

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yes bro... u r correct there are only 2 essencial prime implicant becoz don'care don't consider for EPI
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So we don't consider Don't cares? Sure?
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Yes definitely...
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Ok thanks

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