13 votes 13 votes The Boolean function obtained by adding an inverter to each and every input of an $\text{AND}$ gate is: $\text{OR}$ $\text{XOR}$ $\text{NAND}$ $\text{NOR}$ None of the above Digital Logic tifr2015 digital-logic combinational-circuit digital-circuits + – makhdoom ghaya asked Dec 2, 2015 edited Nov 21, 2022 by Lakshman Bhaiya makhdoom ghaya 2.3k views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply `JEET commented Dec 5, 2019 reply Follow Share @techbd123 @Satbir I am getting $\mathbf{OR}$ as the answer. Can you please check this once. 0 votes 0 votes Satbir commented Dec 5, 2019 reply Follow Share it is called bubbled AND gate. answer is NOR. 0 votes 0 votes `JEET commented Dec 5, 2019 reply Follow Share Yeah, I know that answer is NOR but the truth table represents OR gate as well. 0 votes 0 votes `JEET commented Dec 5, 2019 reply Follow Share A B C 0 0 0 0 1 1 1 0 1 1 1 1 I am getting this truth table after following what is said in the question. So, why not OR gate. 0 votes 0 votes Satbir commented Dec 5, 2019 reply Follow Share $A$ $B$ $A'$ $B'$ $A'.B'$ 0 0 1 1 1 0 1 1 0 1 1 0 0 1 1 1 1 0 0 0 We are getting NOR as output 2 votes 2 votes `JEET commented Dec 5, 2019 reply Follow Share Oh yes that was the mistake. I was comparing with A and B and not A' and B'. Thanks Man!! 0 votes 0 votes Please log in or register to add a comment.
Best answer 17 votes 17 votes Invert-AND = NOR For example, $A'B' = \overline{A+B}$ $[$Note : Invert-OR = NAND, $A'+B' = \overline{A.B}]$ Praveen Saini answered Dec 2, 2015 selected Dec 2, 2015 by Umang Raman Praveen Saini comment Share Follow See all 0 reply Please log in or register to add a comment.