0 votes 0 votes Please some one help me in this question mehul vaidya asked Jan 9, 2019 mehul vaidya 314 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Kunal Kadian commented Jan 9, 2019 reply Follow Share 4? 0 votes 0 votes mehul vaidya commented Jan 9, 2019 reply Follow Share yes but is my explanation correct : BC is C.K. so here BC->E & BCD->A satisfy BCNF but A->F , F->G , C->D , A->G violets BCNF For A->F : Table will be (A,F) {F will be deleted from A,B,C,D,E,F,G} For F->G : Table will Be (F,G) {we already deleted F from A,B,C,D,E,F,G now delete G also } For C->D : Table will be {C,D} {D will be deleted from A,B,C,D,E,F,G} Now Rest of attribute {A,B,C,E} will form one table. Here We archived lossless decomposition , but dependencies BCD->A & A->G lost . Is my explanation correct? 0 votes 0 votes Kunal Kadian commented Jan 9, 2019 reply Follow Share Yes. The 4 tables will be formed in the same way you described, but I think the dependency A-> G will be indirectly present, bcoz of A-> F and F-> G 1 votes 1 votes mehul vaidya commented Jan 9, 2019 reply Follow Share OK THANKS 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes yes 4 tables, CD BCE FG ABCF mohd. ashfaq answered Jan 9, 2019 mohd. ashfaq comment Share Follow See all 0 reply Please log in or register to add a comment.