edited by
910 views

1 Answer

5 votes
5 votes
initially window size(WS) = 1, so we can transfer 1 packet.

after first RTT  WS =2, so we can transfer 2 packet.

after second RTT WS = 4 , so in this we can transfer 4 packet.

after third RTT WS = 8, we can transfer 8 packet.

after fourth RTT WS = 16, transfer 16 packet

after 5th RTT WS = 32, transfer 32 packet.

after 6th RTT WS = 64, transfer 64 packet.

after 7th RTT WS = 128,  transfer 128 packet.

after 8th RTT WS = 256, transfer 256 packet.

after 9th RTT WS will become= 512, so in 10th RTT we transfer 512 packet.

after the 10th RTT total packet send=1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 + 512

                                                         = 1023

but we have to send 2000 packet.

no of packet still remaining=2000-1023=977

so after 10th RTT WS has become = 1024, so remaining 977 packet will be send in 11th RTT.

so RTT require = 11

Related questions

2 votes
2 votes
2 answers
1
Markzuck asked Jan 7, 2019
952 views
Please help, I am getting total number of transmission to get BACK TO 38 as 14 and NOT 15.after 14th, it would have became 38, so no need to consider 15th segment right?
1 votes
1 votes
1 answer
4