0 votes 0 votes https://gateoverflow.in/?qa=blob&qa_blobid=10139953772158305238 a. 1 B. 3 C. 4 D. None gate_forum asked Jan 11, 2019 gate_forum 697 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply kumar.dilip commented Jan 11, 2019 reply Follow Share $1.$ 0 votes 0 votes balchandar reddy san commented Jan 11, 2019 reply Follow Share hamming distance of 1st & 2nd code is 8 and that of 3rd & 4th is 8. so the max. no. of error bits that can be corrected is (HD-1)/2 = 3 0 votes 0 votes kumar.dilip commented Jan 11, 2019 reply Follow Share balchandar reddy san We take the minimum of hamming distance between the codes. Which is 4. Hamming distance = minimum distance of all the codes. 0 votes 0 votes balchandar reddy san commented Jan 11, 2019 reply Follow Share yes..so the answer would be 1. 0 votes 0 votes Please log in or register to add a comment.