@Magma inside we have two loops which have O(n+logn)...
and 2 outside loop runs for O(n)
so overall = 0(n(n+logn)) = O(n2) ?
.
check once ! i have cross checked maybe i missed somewhere...
I am getting 100 :( for Bound=1 loop is running 1*(n+logn) times, for Bound=2 its running 2*(n+logn) times and so on ..
So, the series i am getting is n+2n+4n+8n+... which comes out to be O(n).
kindly correct me if something wrong @srestha@Arjun@Habibkhan
this onehttps://csedoubts.gateoverflow.in/13955/made-easy-mock-2