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plz tell the answer

in Digital Logic
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217 views
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oxE5B ??
0
no ans given as 0xAB
2

Above answer is with the parity bits + message included. But for message answer will be 0xAB.

1 2 3 4 5 6 7 8 9 10 11 12
1 1 1 0 0 1 0 1 1 1 1
P1(parity) P2 M1(message) P3 m2 m3 m4 P4 m5 m6 m7 m8

Now, I'm taking the even parity.

P1 = { 1,3,5,7,9,11} =  1 1 0 0 1 1 ( EVEN)

P2 ={2,3,6,7,10,11} = 1 1 1 0 1 1 ( ODD)

P3 = {4,5,6,7,12}  =    0 0 1 0 1 ( EVEN)

P4 = {8,9,10,11,12} =  1 1 1 1 1 ( ODD)

C4 C3 C2 C1

1      0      1     0   = ( 10th bit position have to be change)

then message with parity will be ==> 0xE5B.

Message = 0xAB.

0
should be 0xE5B

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