1 votes 1 votes plz tell the answer Digital Logic digital-logic hamming-code made-easy-test-series + – suneetha asked Jan 12, 2019 recategorized Mar 4, 2019 by ajaysoni1924 suneetha 620 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply kumar.dilip commented Jan 12, 2019 reply Follow Share oxE5B ?? 0 votes 0 votes suneetha commented Jan 12, 2019 reply Follow Share no ans given as 0xAB 0 votes 0 votes kumar.dilip commented Jan 12, 2019 reply Follow Share Above answer is with the parity bits + message included. But for message answer will be 0xAB. 1 2 3 4 5 6 7 8 9 10 11 12 1 1 1 0 0 1 0 1 1 1 1 1 P1(parity) P2 M1(message) P3 m2 m3 m4 P4 m5 m6 m7 m8 Now, I'm taking the even parity. P1 = { 1,3,5,7,9,11} = 1 1 0 0 1 1 ( EVEN) P2 ={2,3,6,7,10,11} = 1 1 1 0 1 1 ( ODD) P3 = {4,5,6,7,12} = 0 0 1 0 1 ( EVEN) P4 = {8,9,10,11,12} = 1 1 1 1 1 ( ODD) C4 C3 C2 C1 1 0 1 0 = ( 10th bit position have to be change) then message with parity will be ==> 0xE5B. Message = 0xAB. 2 votes 2 votes balchandar reddy san commented Jan 12, 2019 reply Follow Share should be 0xE5B 0 votes 0 votes Please log in or register to add a comment.