MadeEasy Test Series: General Aptitude - Fractions

Question

Three boxes labeled A, B and C have a total of 249 marbles. If 3 dozen marbles are transferred from box ‘A’ to box ‘B’, box ‘B’ will have 5 times the number of marbles in box ‘A’. Instead, if 21 marbles are transferred from box ‘B’ to box ‘C’, the number of marbles in box ‘B’ will be 1.5 times the number of marbles in box ‘C’. How many marbles should be transferred from box ‘A’ or ‘B’ so that the number of marbles in both ‘A’ and ‘B’ is identical?

• 30 from box ‘A’ to box ‘B’
• 30 from box ‘B’ to box ‘A’
• 36 from box ‘A’ to box ‘B’
• 36 from box ‘B’ to box ‘A’

Answer 1

Let x y z be no of marbles in box A B C

acc to ques we get following equations

x+y+z=249

y+36=5(x-36)

y-21=1.5(x+21)

solving this we get x=69 y=129 and z=51

now to have equal marbles in box A and B we transfer k marbles from B to A

129-k=69+k

2k=60

k=30

so ans is b

Comments

please explain me how we get the y-21=1.5(x+21)