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Consider the below Digital Circuit : 

The State Transition diagram on circuit is :

 

 

 

  1.  
in Digital Logic by Loyal (6.9k points)
edited by | 147 views
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I am getting A as an answer but its B i don't know where i am wrong :(
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$B$
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Help here brother :)
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For both state Q and 'Q.

For s = 0. ( latch mode)

For s = 1. ( toggle mode)
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Even I got A.
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@kumar.dilip

s=0 is not always giving latch. Let S=0 and Q=1. Now from the MUX I0 will be selected in this case , i.e I0=Q=1.
Now 1 is given to the inputs of J and K. As both J and K are 1 it toggles the current state Q=1 to Q=0. Thus, forS=0, Q=1 becomes Q=0.

correct me if I am wrong somewhere

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Answer is A

J=K=Y

Y= S'Q + SQ'

Q=0 then Y=S AND Q=1 then Y=S'

Y=0 -> J=K=0, so Qn = Q

Y=1 -> J=K=1, so Qn = Q'

Q S Y Qn
0 0 0 Q - 0
0 1 1 Q'- 1
1 0 1 Q'- 0
1 1 0 Q - 1

correct me if i am wrong.

 

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