Consider the below Digital Circuit :
The State Transition diagram on circuit is :
s=0 is not always giving latch. Let S=0 and Q=1. Now from the MUX I0 will be selected in this case , i.e I0=Q=1.
Now 1 is given to the inputs of J and K. As both J and K are 1 it toggles the current state Q=1 to Q=0. Thus, forS=0, Q=1 becomes Q=0.
correct me if I am wrong somewhere
Answer is A
Y= S'Q + SQ'
Q=0 then Y=S AND Q=1 then Y=S'
Y=0 -> J=K=0, so Qn = Q
Y=1 -> J=K=1, so Qn = Q'
correct me if i am wrong.