3 votes 3 votes Consider the below Digital Circuit : The State Transition diagram on circuit is : Digital Logic digital-logic circuit-output made-easy-test-series + – Na462 asked Jan 13, 2019 edited Mar 4, 2019 by ajaysoni1924 Na462 756 views answer comment Share Follow See all 7 Comments See all 7 7 Comments reply Na462 commented Jan 13, 2019 reply Follow Share I am getting A as an answer but its B i don't know where i am wrong :( 0 votes 0 votes kumar.dilip commented Jan 13, 2019 reply Follow Share $B$ 0 votes 0 votes Na462 commented Jan 13, 2019 reply Follow Share Help here brother :) 0 votes 0 votes kumar.dilip commented Jan 13, 2019 reply Follow Share For both state Q and 'Q. For s = 0. ( latch mode) For s = 1. ( toggle mode) 0 votes 0 votes Vinit Gore commented Jan 27, 2019 reply Follow Share Even I got A. 0 votes 0 votes saptarshiDey commented Jan 28, 2019 reply Follow Share @kumar.dilip s=0 is not always giving latch. Let S=0 and Q=1. Now from the MUX I0 will be selected in this case , i.e I0=Q=1. Now 1 is given to the inputs of J and K. As both J and K are 1 it toggles the current state Q=1 to Q=0. Thus, forS=0, Q=1 becomes Q=0. correct me if I am wrong somewhere 0 votes 0 votes snaily16 commented Jan 28, 2019 reply Follow Share Answer is A J=K=Y Y= S'Q + SQ' Q=0 then Y=S AND Q=1 then Y=S' Y=0 -> J=K=0, so Qn = Q Y=1 -> J=K=1, so Qn = Q' Q S Y Qn 0 0 0 Q - 0 0 1 1 Q'- 1 1 0 1 Q'- 0 1 1 0 Q - 1 correct me if i am wrong. 1 votes 1 votes Please log in or register to add a comment.