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A. X=40,Y=20

B.X=50,Y=10

C.X=30,Y=20

D. X=20,Y=30

From Given data we can conclude:

Remaining Needs: P1= 25 (70-45), P2= 20 (60-40), P3= 60-X , P4= 40 -Y           //  (Max - currently holds)

And, total units of resource is 150

So, Remaining units of resource will be = 150 - (45+40+X+Y) = 150- (85+X+Y)

Now, check option by option;

Option A: X=40,Y=20

Remaining Needs: P1= 25 (70-45), P2= 20 (60-40), P3= 60-40=20 , P4= 40 -20=20

And Remaining units of resource will be = 150 - (85+40+20) = 150-145 =

we can't complete any process with remaining 5 units

So, option A is wrong.

Option B: X=50,Y=10

Similarly for B: Wrong

Option C: X=30,Y=20

Remaining Needs: P1= 25 (70-45), P2= 20 (60-40), P3= 60-30=30 , P4= 40 -20=20

And Remaining units of resource will be = 150 - (85+30+20) = 150-135 =15

we can't complete any process with remaining 15 units

So, option C is wrong.

Option D: X=20,Y=30

Remaining Needs: P1= 25 (70-45), P2= 20 (60-40), P3= 60-20=40 , P4= 40 -30=10

And Remaining units of resource will be = 150 - (85+30+20) = 150-135 =15

Now we can complete P4 first then others . SAFE SEQUENCE

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