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Madeeasy-CBT
jatin khachane 1
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Jan 14, 2019
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jatin khachane 1
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Shobhit Joshi
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Jan 14, 2019
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The elements of $P$ are not having inverse, it should not be a subgroup.
For $Q$, it is not having the identity element.
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Kunal Kadian
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Jan 14, 2019
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Here G is not a group. Inverse doesn't exists for elements of G, but question says that G is a group.
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OneZero
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@aambazinga
exactly.
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