0 votes 0 votes a group of n stations share a 100kbps pure aloha channel .each station outputs a 1000B frame on average every 50 sec . the maximum value of N? answer given as 920 but i am getting 115 please check eyeamgj asked Jan 15, 2019 eyeamgj 508 views answer comment Share Follow See all 8 Comments See all 8 8 Comments reply Manas Mishra commented Jan 15, 2019 reply Follow Share me too getting 115 1 votes 1 votes Kunal Kadian commented Jan 15, 2019 reply Follow Share I am also getting 115. Maybe ans. given is wrong. Can someone else verify ? 1 votes 1 votes Magma commented Jan 15, 2019 reply Follow Share what is the procedure can you tell me ?? 0 votes 0 votes eyeamgj commented Jan 15, 2019 reply Follow Share WHICH PROCEDURE? I USED N*THROUGHPUT OF EACH STATION = AVAILABLE BANDWIDTH 0 votes 0 votes Manas Mishra commented Jan 15, 2019 reply Follow Share @Magma Tt = 0.08 so in 50 sec 1 frame transmitted so in o.o8 sec , 0.08/50 = 0.0016 frame transmitted so our G = 0.0016 now use formula , N * G*e^-2G = 0.184 coming N = 115 1 votes 1 votes Magma commented Jan 15, 2019 reply Follow Share @Manas From where you got 0.184 ??? 0 votes 0 votes Manas Mishra commented Jan 15, 2019 reply Follow Share @Magma efficiency of pure aloha is 18.4 % 1 votes 1 votes Magma commented Jan 15, 2019 reply Follow Share thanks ... actually I forgot that part 0 votes 0 votes Please log in or register to add a comment.