Modification to GATE CS-2001 question on Pointers

Question

Suppose, I have this program…

#include <stdio.h>
#include <stdlib.h>

int *g(void)
{
    int *px;
    px = (int*) malloc (sizeof(int));
    *px = 10;
    return px;
}

int main()
{
   int y=*g(); /* Doubt */
   printf("%d",y);
}

Now, if I modify the line labelled as ‘Doubt’ as :- int y=g(), then in the output, I get a garbage value. I am unable to understand why. Can anyone please explain ?

Comments

Here's the result :- 

https://ide.geeksforgeeks.org/8HFxqVyLfm

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int *g()

$g$ is a function which returs a integer pointer

 

int y=*g();

Read it like this, $int \,\,y={}^*(g());$

Without *, we are giving a pointer to int, without casting so it  gives a garbage value.

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Yeah I figured it out.. Thanks a lot. :)