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Let the following be addresses of IP networks:

  • Network $1: \: 141.21.0.0/16$
  • Network $2: \: 141.22.0.0/16$
  • Network $3: \: 143.22.12.0/24$


Let the IP addresses of three hosts be given as follows:

  • Host A: $141.21.12.19$
  • Host B: $143.21.12.19$
  • Host C: $143.22.11.19$
  • Host D: $141.21.21.21$
  • Host E: $143.22.21.21$

How many of these hosts do not belong to any of the networks?

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3 Answers

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Answer is $3$
Host A belongs to Network1,
Host B belongs to None
Host C belongs to None
Host D belongs to Network2
Host E belongs to None
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Answer is 3

Network 1 id: 141.21.0.0

Network 2 id: 141.22.0.0

Network 3 id: 143.22.12.0

Host A belongs to Network 1
Host D belongs to Network 1

Hosts B, C, E  don't belong to any network.
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Network 1:$141.21.0.0/16$

First Address:$141.21.0.0$  Last Address:$141.21.255.255$

Network 2:$141.22.0.0/16$

First Address:$141.22.0.0$ Last Address:$141.22.255.255$

Network 3:$143.22.12.0/24$

First Address:$143.22.12.0$ Last Address:$143.22.12.255$

so

only A and D satisfy so 3 not satisfy
Answer:

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