There will be no collisions when you insert the elements $94, 37, 29, 40, 84.$ Those elements are placed at the locations $9, 3, 12, 6, 16.$ When you are trying to hash the element $88$, it will collision at the location $3$, so we will apply double hashing on it. It will place at the location $8$. The final hash table is after hashing all elements
$\begin{array}{|c|c|} \hline \text{value} & \text{Location} \\ \hline 102 & 0 \\ \hline 120 & 1 \\ \hline & 2 \\ \hline 37 & 3 \\ \hline 67 & 4 \\ \hline & 5 \\ \hline 40 & 6 \\ \hline 122 & 7 \\ \hline 88 & 8 \\ \hline 94 & 9 \\ \hline & 10 \\ \hline & 11 \\ \hline 29 & 12 \\ \hline 63 & 13 \\ \hline & 14 \\ \hline & 15 \\ \hline 84 & 16 \\ \hline \end{array}$