1 votes 1 votes Which of the following statements is FALSE? There exists a language which is Undecidable and Turing Recognizable. There exists a language which is Decidable and Turing Recognizable. There exists a language which is both Undecidable and not Turing Recognizable. There exists a language which is both Decidable and not Turing Recognizable. Theory of Computation applied-course-2019-mock1 theory-of-computation decidability + – Applied Course asked Jan 16, 2019 recategorized Jul 4, 2022 by Lakshman Bhaiya Applied Course 609 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Turing decidable $\rightarrow$ Recursive language. Turing recognizable $\rightarrow$ Recursive Enumerable Language. Recursive Languages are subsets of REL and if L is recursive and also L is Recursive Enumerable Applied Course answered Jan 16, 2019 Applied Course comment Share Follow See 1 comment See all 1 1 comment reply JashanArora commented Jan 18, 2020 reply Follow Share Not Turing recognisable == Not partially decidable, right? (ie, not even Recursively Enumerable) Can you please hint how C is true? AFAIK, Not partially decidable languages are the languages for which no Turing Machine exists. But they exist for Undecidable languages. If I'm wrong, I'm open to corrections in my understanding. :) 0 votes 0 votes Please log in or register to add a comment.