recategorized by
720 views

1 Answer

0 votes
0 votes
$\frac{5k89k2}{18}$
$18=9 \times 2$
So $5k89k2$ should be divided by $9$ as well as $2$.
As unit digit is even number $5k89k2$ is divisible by $2$.
$\textit{Divisibility rule 9:}$ Sum of digits should be multiple of $9$
$5+k+8+9+k+2 = 24 + 2k$
Now check with options
(A) $\rightarrow$ If $k = 8$  then $24 + 2*8 = 40$ not divisible by $9$.
(B) If $k = 6$ then $24 + 2*6  = 36$ divisible by $9$. Therefore $k=6$ is answer.
Answer:

Related questions

1 votes
1 votes
1 answer
1
Applied Course asked Jan 16, 2019
620 views
The average of $5$ consecutive numbers is $N$. If the next three numbers are also added, the average shallRemain unchangedIncrease by $1$Increase by $1.5$Increase by $2$
1 votes
1 votes
1 answer
2
Applied Course asked Jan 16, 2019
535 views
Study the following table and answer the question:$$\begin{array}{|l|l|l|l|l|} \hline \text{Dry fruits} & \text{% of sugar} & \text{% of protein} & \text{% of Fibre} & \t...
2 votes
2 votes
1 answer
3