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A number $5k89k2$ can be divided by $18$ if $k$ is
  1. $8$
  2. $6$
  3. $1$
  4. More than one value possible
in Others by Junior (659 points) | 75 views

1 Answer

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$\frac{5k89k2}{18}$
$18=9 \times 2$
So $5k89k2$ should be divided by $9$ as well as $2$.
As unit digit is even number $5k89k2$ is divisible by $2$.
$\textit{Divisibility rule 9:}$ Sum of digits should be multiple of $9$
$5+k+8+9+k+2 = 24 + 2k$
Now check with options
(A) $\rightarrow$ If $k = 8$  then $24 + 2*8 = 40$ not divisible by $9$.
(B) If $k = 6$ then $24 + 2*6  = 36$ divisible by $9$. Therefore $k=6$ is answer.
by Junior (659 points)
0

@Applied Course there can be multiple values for k, for example you replace k with 15, and 18 can still divide the number hence option(D) should be the correct option, right?

0

@chauhansunil20th k must be single digit as given format in question.

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