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total no of binary operation $n^{n^{2}}$

no of commutative binary operation $n^{((n^{2}+n)/2)}$

no of non commutative binary operation $n^{n^{2}}$  $-$$n^{((n^{2}+n)/2)}$

probability of non commutative $n^{n^{2}}$$-$$n^{((n^{2}+n)/2)}$$/$$n^{n^{2}}$

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Supremo asked Jan 28, 2017
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plz explain the meaning of question