search
Log In
0 votes
80 views
A system uses selective repeat protocol with window size of 4. If each packet carries 5000 bits , then the time taken to tranfer 5 milion bits of data, if the distance between sender and receiver is 2500km , the propagation speed is 2* 10^8 m/s and data rate is 1Mbps. We assume no data or ACK is lost
in Computer Networks
closed by
80 views
0
is it 7.5 sec?
0
answer given 11.25
0
i am trying to calculate the efficiency and then find the effective bandwidth.
0

@balchandar reddy san

@jatin khachane 1

they are sending the second round of packets once all the ack of the previous round is received.

i.e.. when all the ack of the 4 packets sent in the first round arrives we start to transmit second round. This is not how SR protocol works

Hence, the answer given is wrong.

answer should be 7.49.

 

Related questions

1 vote
2 answers
1
297 views
Consider a TCP connection between two machines (A and B) in an environment with 0% packet loss. Assume the round trip time (RTT) between the two machines is 4 [seconds], and the segment size is 3 [Kbytes]. The bandwidth of the connection is 500 [kbps]. What is the ... buffer close to zero. I.e., TCP packets are continuously, back-to-back, sent out of the sender before the first ack arrives back.)
asked Jan 18, 2019 in Computer Networks jatin khachane 1 297 views
0 votes
0 answers
2
...