0 votes 0 votes A treasure has 6 similar gold coins and 9 silver coins. If 4 coins are to be randomly selected without replacement, the probability that the first 2 selected are gold and the last 2 silver ghostman23111 asked Jan 19, 2019 recategorized Jan 19, 2019 by ghostman23111 ghostman23111 510 views answer comment Share Follow See 1 comment See all 1 1 comment reply balchandar reddy san commented Jan 19, 2019 reply Follow Share Gold coins: 6, Silver coins: 9 First pick being gold is: 6/15 Gold coins: 5, Silver coins: 9 Second pick being gold is : 5/14 Gold coins: 4, Silver coins: 9 Third pick being silver is : 9/13 Gold coins: 4, Silver coins: 8 Fourth pick being silver is : 8/12 Probability: 6/15 * 5/14 * 9/13 * 8/12 1 votes 1 votes Please log in or register to add a comment.
0 votes 0 votes (6C2 *9C2)/15C4 Ravi kumar singh answered Jan 19, 2019 Ravi kumar singh comment Share Follow See 1 comment See all 1 1 comment reply Meet2698 commented Feb 17, 2019 reply Follow Share The question specifically mentions that the first 2 must be Gold.In your case,any 2 of the selected coins can be Gold. 0 votes 0 votes Please log in or register to add a comment.