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  • The $(r-1)$’s complement of a number can be found using formula $(r^{n}-r^{-m}-N)$ where $r$ is base of the number $N$ having $n$ digits and $m$ digits in integral an fraction part respectively. We have been given some decimal numbers as shown below:
    $(i) 325$                    $(ii) 325.893$
    $(iii) –819$                 $(iv) –517.67$
    How many $(r – 1)’s$ complement of above decimal numbers can be calculated using mentioned formula?

in Digital Logic by (195 points)
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i think number is given in decimal so 9's complement will be unique for every number.
yes, but (i) and (iv) maynot be decimal.
What is ans. given??

(iii)180  and (iv)482.32 ??

1 Answer

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Here r=radix number or base

integer part n digits

fraction part m digits

N= positive given number.

$\left ( i \right ) 325$



$\left ( ii \right )325.893$



Similar for $(iii)$ and $(iv)$ too.-ve willnot have any extra effect on numbers

Ref: Page 27 here

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