0 votes 0 votes The number of ways in which we can place 3 white pawns and 3 black pawns on a 3 × 3 Chessboard is equal to himgta asked Jan 23, 2019 himgta 617 views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Show 3 previous comments aanchal008 commented Jan 23, 2019 reply Follow Share first select 6 positions from 9 position available which can be done in 9C6 ways. then from 6 places chosen can be permutated as 6!/(3!*3!). so number of ways are 9C6*(6!/(3!*3!))=1680. 0 votes 0 votes Ram Swaroop commented Jan 26, 2019 reply Follow Share https://gateoverflow.in/296427/made-easy-adv-mock 0 votes 0 votes Abhineet Singh commented Jan 4, 2021 reply Follow Share what is wrong with this method… Initially the chess board is empty, so I can place the 1st pawn in 9 ways, now 8 places are left and I can place the 2nd pawn in 8 ways and so on, the last pawn can be placed in 4 ways. So total = 9*8*7*6*5*4 0 votes 0 votes Please log in or register to add a comment.