0 votes 0 votes The number of ways in which we can place 3 white pawns and 3 black pawns on a 3 × 3 Chessboard is equal to himgta asked Jan 23, 2019 himgta 647 views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply OneZero commented Jan 23, 2019 i edited by OneZero Jan 23, 2019 reply Follow Share is it 12320? 0 votes 0 votes himgta commented Jan 23, 2019 reply Follow Share ans is given 1680 @Shaik Masthan @MiNiPanda @Mk Utkarsh plz explain! 0 votes 0 votes OneZero commented Jan 23, 2019 reply Follow Share @himgta select 6 positions out of 9 positions. this can be done in 9C6 ways. from these selected positions, arrange the pawns in them in 6!/3!*3! hance the answer is 9C6*6!/3!*3! = 1680. 1 votes 1 votes aanchal008 commented Jan 23, 2019 reply Follow Share first select 6 positions from 9 position available which can be done in 9C6 ways. then from 6 places chosen can be permutated as 6!/(3!*3!). so number of ways are 9C6*(6!/(3!*3!))=1680. 0 votes 0 votes Ram Swaroop commented Jan 26, 2019 reply Follow Share https://gateoverflow.in/296427/made-easy-adv-mock 0 votes 0 votes Abhineet Singh commented Jan 4, 2021 reply Follow Share what is wrong with this method… Initially the chess board is empty, so I can place the 1st pawn in 9 ways, now 8 places are left and I can place the 2nd pawn in 8 ways and so on, the last pawn can be placed in 4 ways. So total = 9*8*7*6*5*4 0 votes 0 votes Please log in or register to add a comment.