689 views
0 votes
0 votes
Let S(x) be the predicate "x is a student",T(x) be the predicate "x is a teacher"and Q(x,y) be the predicate "x has asked y a question" where the domain consists of all people associated with the school. Use quantifiers to express the statement.
"Some student has never been asked a question by a Teacher" 
A
∃x(S(x) ∨ ∀y(T(y)) → ¬ Q(x,y)))
B
¬∀x(S(x) ∨ ∀y(T(y)) → ¬ Q(y,x)))
∃x(S(x) ∧ ∀y(T(y)) → ¬ Q(y,x)))
¬∀x(S(x) ∧ ∀y(T(y)) → Q(x,y)))

 

All options seems to be wrong to me. But the last one looked closest. Can anyone pls help me in understanding this?

What I am up to –

As far as i know, with ∃, we always use ‘^’ and with we use ‘→ ’.

So, The statement would be translated as-

∃x∀y S(x) ∧ T(y) ∧ ¬Q(y,x)

=> ∃x∀y ¬( ¬( S(x) ∧ T(y) ) Q(y,x) )

=> ¬ ∀x∃y ( ( S(x) ∧ T(y) ) → Q(y,x) )  [ ¬P v Q = P→Q ]

None of the options are matching….

Please log in or register to answer this question.

Related questions

0 votes
0 votes
0 answers
1
1 votes
1 votes
1 answer
3
nishant279 asked Oct 18, 2017
1,257 views
A = ∃x (P(x) ^ Q(x)).B = ∃x P(x) ^ ∃x Q(x).Which is correct?a) A = Bb) B = Ac) A <= Bd) None of ThesePlease Explain.
0 votes
0 votes
0 answers
4
nishant279 asked Oct 18, 2017
475 views
A = ∃x(P(x)^Q(x))B = ∃x P(x) ^ ∃x Q(x), which is correct?a) A <= Bb) A = Bc) B = Ad) None of ThesePlease Explain.